Given the head of a linked list, remove the nth node counting from the end of the list and return the head of the resulting list.
head = [1,2,3,4,5], n = 2[1,2,3,5]head = [1], n = 1[]Solve it in the editor. Sign in free to run your Python or JavaScript against test cases, get a verdict, and track your attempts.
Solve on FeatCode →A chain of nodes, each pointing to the next. No random access like an array, but insertion and deletion at a known position is O(1), and many classic problems come down to careful pointer rewiring.
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Original problem on LeetCode ↗